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───✱*.｡:｡✱*.:｡✧*.｡✰*.:｡✧*.｡:｡*.｡✱ ───

　　　　　　　　6//?r=⭐　&d=2024/6/3 20:53:42　&b=lwyz29bk

Merge JavaScript objects in array with same key - Stack Overflow

https://stackoverflow.com/questions/33850412/merge-javascript-objects-in-array-with-same-key | function mergeBasedOnKey(list)

　　　　　　　　6//?r=⭐　&d=2024/6/3 21:00:42　&b=lwyzb9ap

javascript - Merge two array of objects based on a key - Stack Overflow

https://stackoverflow.com/questions/46849286/merge-two-array-of-objects-based-on-a-key | const keyValuePair = function(arr1, arr2)

　　　　　　　　6//?r=⭐　&d=2024/6/4 09:04:40　&b=lwzp6agp

JavaScript Join Identical Adjacent Elements in an Array - Stack Overflow

https://stackoverflow.com/questions/54300223/javascript-join-identical-adjacent-elements-in-an-array | const data = [‘a’, ‘a’, ‘a’, ‘b’, ‘b’, ‘c’, ‘c’, ‘c’, ‘d’, ‘e’, ‘e’];

const res = […data.reduce((a,c)⇒{ return a.set(c, (a.get(c)||"") + c); }, new Map()).values()];

console.log(res);

const data = [‘a’, ‘a’, ‘a’, ‘b’, ‘b’, ‘c’, ‘c’, ‘c’, ‘d’, ‘e’, ‘e’];

const res = [];

for(let i = 0; i < data.length; i++){ const c = data[i]; let str = c; for(let j = i + 1; j < data.length && c === data[j]; j++,i++){ str += c; } res.push(str); }

console.log(res);

　　　　　　　　6//?r=⭐　&d=2024/6/4 09:03:05　&b=lwzp48x8

Javascript: how to combine two adjacent elements of an array - Stack Overflow

https://stackoverflow.com/questions/28174500/javascript-how-to-combine-two-adjacent-elements-of-an-array

var array = [‘a’, ‘bb’, ‘ccc’, ‘d’, ‘e’, ‘f’, ‘g’, ‘hhhhhhhh’]; for (var i = 1; i < array.length - 1; i++) { while (array[i].length ⇐ i && typeof array[i + 1]!=‘undefined’ ) { array[i] += array[i + 1]; array.splice(i + 1, 1); } } console.log(array.join(’, ’));

　　　　　　　　6//?r=⭐　&d=2024/6/4 15:14:43　&b=lx02e6iy

AiChat ai.gptyylx.com

https://ai4s.gpt-666.com/#/chat/1717483655268 | js代码实现arrayInput变为arrayOutput。 const arrayInput = [ [ "", “val1” ], [ “img”, “val2” ], [ “a”, “val3” ], [ “img”, “val4” ], [ “img”, “val5” ] ]

arrayOutput = [ [ "", “val1” ], [ “img”, “val2” ], [ “a”, “val3” ], [ “img”, [“val4”,“val5”] ], ]

　　　　　　　　6//?r=⭐　&d=2024/6/4 15:43:57　&b=lx03frv4

ChatGAi

https://chatgai.lovepor.cn/?utm_source=bing&utm_campaign=GPT&utm_Group=HXC&utm_Keyword=%E5%9C%A8%E7%BA%BFgpt&msclkid=8bb22bb677d21e2405714de8b2c4b560 |

const arrayInput = [
    ["", "val1"],
    ["img", "val2"],
    ["a", "val3"],
    ["img", "val4"],
    ["img", "val5"]
];
 
const arrayOutput = arrayInput.reduce((acc, curr) => {
    const lastItem = acc[acc.length - 1];
    if (lastItem && curr[0] === lastItem[0]) {
        if (!Array.isArray(lastItem[1])) {
            lastItem[1] = [lastItem[1]];
        }
        lastItem[1].push(curr[1]);
    } else {
        acc.push(curr);
    }
    return acc;
}, []);
 
console.log(arrayOutput);

const arrayInput = [
    ["", "val1"],
    ["img", "val2"],
    ["a", "val3"],
    ["img", "val4"],
    ["img", "val5"]
];
 
const arrayOutput = arrayInput.reduce((acc, curr) => {
    const lastItem = acc[acc.length - 1];
    if (curr[0] === "img" && lastItem && lastItem[0] === "img") {
        if (!Array.isArray(lastItem[1])) {
            lastItem[1] = [lastItem[1]];
        }
        lastItem[1].push(curr[1]);
    } else {
        acc.push(curr);
    }
    return acc;
}, []);
 
console.log(arrayOutput);

一位高大威猛的鲁迅站在破旧的北京胡同中，背景是烟雾弥漫的火红天空，展现出浓厚的暗黑文学氛围。他笔挺的西装上布满污渍，手持一支烟斗，眼神中透露出坚定和思考的力量。这幅画面呈现出震撼人心的现代主义风格，凸显出人物的雕塑般精细的肌肉线条，立体感极强，仿佛可以跃然纸上。

js代码实现arrayInput变为arrayOutput。可以被3整除，而且相邻的值合并，其余不变。 const arrayInput = [“2”,“9”,“4”,“12”,“21”];

arrayOutput = [ [ “first”, “2” ], [ “img”, “9” ], [ "", “4” ], [ “img”, [“12”,“21”] ], ]

const arrayInput = ["val1","img2","dat3","img4","img5"];
 
function convertArray(input) {
    const arrayOutput = [];
 
    for (let item of input) {
        let prefix = "";
        if (item.startsWith("img")) {
            prefix = "img";
            item = item.substring(3);
            if (!arrayOutput.find(arr => arr[0] === "img")) {
                arrayOutput.push(["img", []]);
            }
            arrayOutput.find(arr => arr[0] === "img")[1].push(item);
        } else {
            let number = item.match(/\d+/)[0];
            let val = item.replace(number, "");
            arrayOutput.push([prefix, val + number]);
        }
    }
    
    return arrayOutput;
}
 
const arrayOutput = convertArray(arrayInput);
console.log(arrayOutput);

这段代码定义了一个convertArray函数，将arrayInput按照题目要求转换为arrayOutput的格式。在遍历arrayInput时，根据元素的不同开头或数字，处理对应的情况，并将转换后的结果存入arrayOutput中。

　　　　　　　　6//?r=⭐　&d=2024/6/5 11:10:59　&b=lx194kjl

ChatGPT

https://chatgpt.com/c/67d60404-645f-44fb-9964-2e72489b8d16

const arrayInput = [“2”, “9”, “4”, “12”, “21”];

const arrayOutput = []; let temp = [];

arrayInput.forEach((item, index) ⇒ { if (parseInt(item) % 3 === 0) { if (temp.length > 0) { temp.push(item); } else { temp = [item]; }

    if (index === arrayInput.length - 1 || parseInt(arrayInput[index + 1]) % 3 !== 0) {
        arrayOutput.push(["img", temp.length > 1 ? temp.slice() : temp[0]]);
        temp = [];
    }
} else {
    arrayOutput.push(["", item]);
}

});

// Add the “first” label to the first element if (arrayOutput.length > 0) { arrayOutput[0][0] = “first”; }

console.log(arrayOutput);

　　　　　　　　6//?r=⭐　&d=2024/6/6 10:59:14　&b=lx2o5bsu

Array.from() - JavaScript | MDN

https://developer.mozilla.org/zh-CN/docs/Web/JavaScript/Reference/Global_Objects/Array/from |

　　　　　　　　6//?r=⭐　&d=2024/6/6 14:25:15　&b=lx2vi95x

Emoji 的处理 - 使用正则表达式匹配所有 Emoji-腾讯云开发者社区-腾讯云

https://cloud.tencent.com/developer/article/1832681 | /(\ud83c[\udf00-\udfff])|(\ud83d[\udc00-\ude4f\ude80-\udeff])|[\u2600-\u2B55]/g

\d\S\S\S\w+\S.\s\S\w+\S\d{2,4}\S\d{1,2}\S\d{1,2}\s\d{1,2}\S\d{1,2}\S\d{1,2}. \d\S\S\S\w+\S.\s\S\w\S\d+\S\d+\S\d+\s\d+\S\d+\S\d+.

从 Map 构建数组从 NodeList 构建数组序列生成器（range）

const floatLayer = document.querySelector(‘float-window#usurpFrame’); floatLayer.appendChild(treeContainer);

const usurpFrame = document.querySelector(‘float-window#usurpFrame’); createElem(‘createTag’, ‘containerElem’, ‘attachMethod’, ‘schemaOut’, ‘valueStr’, ‘className’, ‘id’);